Given: The battleship and enemy ships 1 and 2 lie along a straight line. Neglect air friction. Consider the motion of the two projectiles fired at t = 0. Their initial speeds are different and they reach different maximum heights h_{1 }and h_{2}. What is the ratio of the time of flight, t _{1} and t_{2} respectively, that the shells reach?

1. t_{1} / t_{2} = 2 (√ h_{1} / h_{2})

2. t_{1} / t_{2} = 1/ √2 (√ h_{1} / h_{2})

3. t_{1} / t_{2} = 2 (√ h_{2} / h_{1})

4. t_{1} / t_{2} = 1/2 (√ h_{1} / h_{2})

5. t_{1} / t_{2} = (√ h_{1} / h_{2})

6. t_{1} / t_{2} = 1/2 (√ h_{2} / h_{1})

7. t_{1} / t_{2} = h_{2} / h_{1}

8. t_{1} / t_{2} = √2 (√ h_{1} / h_{2})

9. t_{1} / t_{2} = (√ h_{2} / h_{1})

10. t_{1} / t_{2} = (h_{1} / h_{2})

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Symmetrical Launch concept. You can view video lessons to learn Symmetrical Launch. Or if you need more Symmetrical Launch practice, you can also practice Symmetrical Launch practice problems.

How long does this problem take to solve?

Our expert Physics tutor, Juan took 7 minutes and 53 seconds to solve this problem. You can follow their steps in the video explanation above.